网站制作做站长挣钱建筑施工组织设计毕业设计

算法的核心是：计算当前数和前一个数的差值,用该差值和以前最小的连续数的差值作比较；如果当前的差值更小，则发现了更小的连续数的差值；如果当前的差值更大，则沿用以前的最小连续数差值作为新的最小连续数差值。

MinDiffBetweenNeighborNumbersTest.java：

import java.util.Random;public class MinDiffBetweenNeighborNumbersTest {public static void main(String[] args) {Random random = new Random();int[] nums = {1,10,11,2,5,7,9,100,200,200,300};int length = nums.length;// 99,98      2,1    52,51   66,63// 求相差最小的2个相邻的数的差值( 即相差的绝对值 )int[][] dp = new int[length][3];// dp[i][0] 存储的是较大的数// dp[i][1] 存储的是较小的数// dp[i][2] 存储的是两数差值的绝对值for (int i = 0; i < length; i++) {int num = nums[i];if( i==0 ){dp[i][0] = num;dp[i][1] = num;dp[i][2] = 0;}else{int num_prev = nums[i-1];if( i == 1 ){if( num > num_prev ){dp[i][0] = num;dp[i][1] = num_prev;}else {dp[i][0] = num_prev;dp[i][1] = num;}dp[i][2] = Math.abs( num - num_prev );}else {// 计算当前数和前一个数的差值,用该差值和以前最小的连续数的差值作比较；如果当前的差值更小，则发现了更小的连续数的差值；如果当前的差值更大，则沿用以前的最小连续数差值作为新的最小连续数差值int diff = Math.abs(num - num_prev);int diff_prev = dp[i - 1][2];if( diff < diff_prev){if( num> num_prev ){dp[i][0]= num;dp[i][1]= num_prev;}else {dp[i][0]= num_prev;dp[i][1]= num;}dp[i][2] = diff;}else {dp[i][0] = dp[i-1][0];dp[i][1] = dp[i-1][1];dp[i][2] = diff_prev;}}}}int[] result = dp[length - 1];System.out.println( result[0] + " 和 " + result[1] + " 相差 " + result[2] );}
}